Dengan menggunakan salah satu indikator yang sesuai larutan CH3COONa. 0,2 M dengan ka = 2×10-5 akan berwarna

[OH-] = √Kw / Ka . M
[OH-] = √10^-14 / 2 x 10^-5 x 2 x 10^-1
[OH-] = √10^-9 x 10^-1
[OH-] = √10^-10
[OH-] = 10^-5

pOH = -log[OH-]
pOH = -log10^-5
pOH = 5

pH = 14 - 5
pH = 9

→ Atau :

pH = 1/2 (14 + pKa + log [G])
pH = 1/2 (14 + (-log2x10^-5) + log2x10^-1)
pH = 1/2 (14 + 5 - log2 - 1 + log2)
pH = 1/2 (18 + 5 - 1)
pH = 1/2 (18)
pH = 9

[ pH 8 - 11 = berwarna Biru ]