tolong bantuin yaa!!!

diketahui:
m = 5kg
∆t = 25°
C.air = 4200J/kg°C
U = 2.200.000J/kg°C

ditanya:
Q

dijawab:
Qab = m.c.∆t
Qab = 5×4200×75
Qab = 1.575.000

Qbc = m.U
Qbc = 5×2.200.000
Qbc = 11.000.000

Qabc = Qab+Qbc
Qabc = 1.575.000 + 11.000.000
Qabc = 12.575.000J
Qabc = 12.575kJ