Matematika

Pertanyaan

f(x)=4x-2/x-5
g(x)=x+3
fog-¹(5) adalah?

2 Jawaban

  • f(g(x)) = (4(x+3)-2)/(x+3)-5
    f(g(x)) = (4x +10)/(x-2)
    y = (4x+10)/(x-2)
    xy - 2y = 4x+10
    xy - 4x = 2y +10
    x (y-4) = 2y+10
    x = (2y+10)/(y-4)
    fog^-1(x) = (2x+10)/(x-4)
    fog^-1(5) = (2(5)+10)/((5)-4)
    fog^-1(5) = 20/1 = 20
  • Fungsi invers

    f(x) = (4x -2)/(x- 5)(
    g(x) =  x+3  ---> g⁻¹ (x+3) = x
    g⁻¹(5)= ..
    x+3 = 5 --> x = 5-3 = 2
    g⁻¹(5) = 2

    fog⁻¹ (5) = f { g⁻¹(5)} = f (2)

    f0g⁻¹ (5) = { 4(2) - 2} / {2-5} = (8-2)/(-3)
    fog⁻¹ (5)= 6/-3 = - 2

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