dik: g(x) = x+3 dan (f.g)=xpangkat2-4 maka f(x-2)=......

[tex]g(x)=x+3 \\ (f\circ g)(x)=x^2-4 \\ f(g(x))=x^2-4 \\ f(x+3)=x^2-4 \\ f(x+3-3)=(x-3)^2-4 \\ f(x)=x^2-6x+9-4 \\ f(x)=x^2-6x+5[/tex]