assalamualaikum... tolong bantu saya kak.. terimah kasih

KALOR

m1 = 200 gr, t1 = 30 °C
m2 = 100 gr, t2 = 80 °C
t = __?

t = (m1 t1 + m2 t2) / (m1 + m2)
t = (200 • 30° + 100 • 80°) / (200 + 100)
t = 14000° / 300 = 46⅔ °C ← jwb