Persamaan garis singgung kurva f(x) = x²-x-8 sejajar garis 4x + 2y = 0

y= x²-x-8
y'=m= 2x-1
m2 dari 4x + 2y =0 => y= -2x + 0 => -2
kalau sejajar m1=m2 => 2x-1= -2 => x= -1/2
cari nilai y => y= (-1/2)² - (-1/2) - 8 => y= - 29/4
masukkan ke persamaan y-y1 = m ( x-x1 ) => y- (-29/4) = -2( x- (-1/2))
=> y+ 29/4 = -2x - 1 => y = -2x - 1 - 7,25 => y= -2x -8,25
jadi pers garisnya adalh y = -2x - 8,25