volume sebuah kerucut 1.232 cm dan panjang jari alasnya 7 cm luas selimut kerucut

[tex]V=1232=1232 :\frac{22}{7} \times \pi = 392 \pi \\ r = 7 \\ V=\pi \times r^2\times t \\ 392 \pi = \pi\times 7^2\times t \\ 392 = 49t \\ t=8 \\ \\ L_s=2\pi rt = 2\times\pi\times 7\times 8 = 112\pi$ cm^2$[/tex]

V = 1/3phi x r2 x t = phi x r x s 1232 = 1/3 x 22/7 x49 x t 1232 x 3 = 1 x 22 x 7 x t 3696 = 154 t t = 3696 : 154 t = 24 cm s = 25 cm (akar t2 + r2) #luas selimut phi x r x s 22/7 x 7 × 25 550 cm2