1.Diketahui 3x^3 - 4x^2 - 13x - 5 = (ax + B) (x-3) (x + 1) + c nilai A - 2 (B + C) [soal suku banyak] A. -3 B. -1 C. 0 D. 3 E. 5 Tolong bantu kak pliss....
Matematika
Miko087
Pertanyaan
1.Diketahui 3x^3 - 4x^2 - 13x - 5 = (ax + B) (x-3) (x + 1) + c nilai A - 2 (B + C) [soal suku banyak] A. -3 B. -1 C. 0 D. 3 E. 5 Tolong bantu kak pliss....
1 Jawaban
-
1. Jawaban DB45
sukubanyak
3x³ - 4x² -13x - 5 = (ax+b)(x-3)(x+1)+c
.
.....3....-4....-13....-5
3..........9....15.....6
.....3....5......2......1
-1.......-3.....-2.
....3.....2.....0
hb = 3x + 2 = (ax+b)
sisa= 1 = c
a = 3, b = 2 , c = 1
nilai a - 2(b+c) = 3 -2(2+1) = 3 - 2(3)
a - 2(b-c) = 3 -6 = -3