Tlng dibantu ya..bsk mau dikmpl Trima ksh

1.
U3
a + 2b = 9
a = 9 - 2b

U5 + U7
a + 4b + a + 6b = 36
2a + 10b = 36
2(9-2b) + 10b = 36
18 - 4b + 10b = 36
6b = 18
b = 3

a = 9 - 2.3 = 9 - 6 = 3

S = 1/2 n ( 2a + (n-1)b )
S10 = 1/2 . 10 (2.3 + 9.3)
S10 = 165

2.
f(2) = ( 3.2 - 1 ) / ( 1 + 2.2)
f(2) = 5/5 = 1

3.
(3 - akar (2x + 9) ) (3 + akar (2x + 9)
= 9 - (2x + 9)
= - 2x

-2x / x ( 3 + akar (2x + 9) =>x bisa dicoret

sehingga limit x-> 0
= -2 / ( 3 + akar 9 )
= - 2/6
= -1/3

1. U3= 9=a+ 2b (pers 1)
U5 + U7 = 36 = 2a +4b+6b
=2a +10b (pers 2)
-----------------------------'
(1) 18 = 2a + 4b
(2)36= 2a +10b
----------------- -
-18= -6b
B = 3 ---> (1) 18 =2a+12 ----> a =3
S10 = 1/2*10(2*3+9*3)
= 5*(6+27) = 165
2. f (2) = (3*2-1)/1+2*2
= 5/5 = 1