Hitunglah pH larutan dari 100 ml larutan(NH4)2SO4 0,05 M. Jika dik (Kb NH4OH = 10–5

2NH4OH +H2SO4 =(NH4)2SO4 + 2H2O


[NH4OH]=2 . 5.10^-2
=10^-1
[OH]=√Kb .M
=√10^-5 .10^-1
=√10^-6
=10^-3
pOH=3
pH=11