Tolong dijawab. Bsok UNBK ipa

MEDAN LISTRIK

Qr = 3 C, Qr' = 1 C
Qs = 4 C, Qs' = 6 C
r = 10 cm, r' = 5 cm
F = 4 N, F' = __?

Gaya Coulomb
F = k Q1 Q2 / r²

Perbandingan
F' / F = (k Qr' Qs' / r'²) / (k Qr Qs / r²)
F' / F = (Qr' / Qr) (Qs' / Qs) (r / r')²
F' / 4 = (1/3) (6/4) 10/5)²
F' / 4 = ⅓ •3/2 • 2²
F' / 4 = 2
F' = 8 N ← jwb

F = q1 . q2 / r^2
4N = 3 x 4 / 10^2
4N = 12 / 100


F = q1 . q2 / r^2
F2 = 1 x 6 / 5^2
F2 = 6/25 

bandingkan

4N = 12 / 100
F2 = 6/25
⇒⇒⇒⇒ 4 N = 3/25
⇒⇒⇒⇒F2  = 6/25 ⇔⇔kita lihat dari 3/25 dengan 6/25 ⇒⇒diperbesar 2 x , yaudah kalau begitu F2 = 4 x2 = 8 N

Terima kasih