ada yang bisa membantu?

[tex]A^{2x} = 2 \\ \\ \frac{A^{5x}-A^{-5x}}{A^{3x}+A^{-3x}} = \frac{A^{5x}-\frac{1}{A^{5x}}}{A^{3x}+\frac{1}{A^{3x}}} \\ \frac{A^{5x}-A^{-5x}}{A^{3x}+A^{-3x}} = \frac{\frac{A^{10x}-1}{A^{5x}}}{\frac{A^{6x}+1}{A^{3x}}} \\ \frac{A^{5x}-A^{-5x}}{A^{3x}+A^{-3x}} = \frac{A^{3x}(A^{10x}-1)}{A^{5x}(A^{6x}+1)} \\ \frac{A^{5x}-A^{-5x}}{A^{3x}+A^{-3x}} = \frac{A^{10x}-1}{A^{2x}(A^{6x}+1)} \\ \frac{A^{5x}-A^{-5x}}{A^{3x}+A^{-3x}} = \frac{(A^{2x})^{5}-1}{A^{2x}((A^{2x})^{3}+1)} \\[/tex]

[tex]\frac{A^{5x}-A^{-5x}}{A^{3x}+A^{-3x}} = \frac{2^{5}-1}{2((2)^{3}+1)}\\ \frac{A^{5x}-A^{-5x}}{A^{3x}+A^{-3x}} = \frac{31}{18}[/tex]

Mohon ralatnya....