Tolongg jawab'in yyaaa ...

F1x = 6 cos30 = 6((1/2)√3)=3√3 N
F1y = 6 sin30 = 6(1/2) = 3 N
F2x= 6 cos30 = 6((1/2)√3)=3√3 N
F2y = 6 sin30 = 6(1/2) = 3 N
F2x = −3√3 N (arahnya ke kiri)
∑Fx = F1x + F2x = 3√3 + (-3√3) = 0
∑Fy = F1y + F2y = 3 + 3 = 6
R = √((∑Fx)²+(∑Fy)²) = √(0²+6²) = √36 = 6 N