Matematika

Pertanyaan

Jika f(x) = x^2 -2 dan g(x) = x^2 + 2 (fog)(x) - (gof)(x) =

2 Jawaban

  • (fog)(x)
    = (x²+2)² - 2
    = x^4 + 4x² + 4 -2
    = x^4 + 4x^2 +2

    (gof)(x)
    = (x²-2)² +2
    = x^4 + 4x² + 4 +2
    = x^4 +4x² + 6

    (fog)(x) - (gof)(x)
    = x^4 + 4x^2 +2 - (x^4 +4x^2 + 6)
    = 2-6
    = -4
  • f(x) = x^2 - 2
    g(x) = x^2 + 2
    (fog)(x) - (gof)(x) = ((x^2+2)^2 - 2) - ((x^2-2)^2 + 2
    = ((x^4 + 4x^2 + 4) - 2) - ((x^4 - 4x^2 + 4) + 2)
    = (x^4 + 4x^2 + 2) - (x^4 - 4x^2 + 6)
    = -4

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