tentukan nilai x dan y dengan metode determinan 2x + 3y = 13 3x - 4y = -6

[tex] x= \frac{\left|\begin{array}{ccc}13&3\\-6&-4\end{array}\right| }{\left|\begin{array}{ccc}2&3\\3&-4\end{array}\right| } = \frac{-52+18}{-8-9}= \frac{-34}{-17}=2 \\ \\ \\ y= \frac{\left|\begin{array}{ccc}2&3\\13&-6\end{array}\right| }{\left|\begin{array}{ccc}2&3\\3&-4\end{array}\right| }= \frac{-12-39}{-8-9}= \frac{-51}{-17}=3 [/tex]

ini jawabannya semoga membantu