tolong bantu pake caranya ~~

24. [tex]= \ \textless \ ABC + \ \textless \ AOC = 180' \\ = \ \textless \ AOC = 100'[/tex]




25. [tex]= AB^{2} = AO^{2} - OB^{2} \\ = AB^{2} = 34^{2} - 16^{2} \\ = AB^{2} = 1156 - 256 \\ = AB = \sqrt{900} \\ = AB = 30[/tex]





26. [tex] = \ \textless \ AOB + \ \textless \ BOC = 180' \\ = 115' + \ \textless \ BOC = 180' \\ = \ \textless \ BOC = 65' \\ karena \ \textless \ BCO = \ \textless \ OBC = \ \textless \ BOC jadi \ \textless \ OBC = 65'[/tex]







27. [tex]= \frac{\ \textless \ AOB}{\ \textless \ BOC} = \frac{busur AB}{busur BC} \\ = \frac{50}{80} = \frac{AB}{64} \\ = \frac{5}{8} = \frac{AB}{64} \\ = 320 = 8AB = AB = 40[/tex]