tolong bantu jawab no 13 dan 14 dengan cara

jadi jawabanya nomor
13. A
14. C

13)
Keadaan A
FA = 3 N
Q1 = 2Q
Q2 = 1Q
r = 5 cm

Keadaan B
Q1 = 1Q
Q2 = 8Q
r = 10 cm
FB = ?

F = k.Q1.Q2 /r^2
Nilai k sama
Sehingga bs kita pakai perbandingan:
FB / FA = {(Q1.Q2)B / (Q1.Q2)A} . {(rA/rB)^2}
FB / FA = (1Q.8Q)/(2Q.1Q) . (5/10)^2
FB / FA = (8 / 2) . (1/4)
FB / FA = 4 . (1/4)
FB / FA = 1
FB = 1 . FA
FB = 3 N
Jawaban A

14)
*Rangkaian 1
1/Rp = 1/3 + 1/3 + 1/3
1/Rp = 3/3
Rp = 1 ohm

Rtotal = 3 ohm + Rp = 3 ohm + 1 ohm = 4 ohm

I = V / Rtotal = 6 volt / 4 ohm
I = 1,5 Ampere

*Rangkaian 2
Yg atas R seri yg bawah jg Rseri
Rseri1 = 3 + 3 = 6 ohm
Rseri2 = 3 + 3 = 6 ohm

Rtotal = Rparalel
1/Rtot = 1/Rseri1 + 1/Rseri2
1/Rtot = 1/6 + 1/6
1/Rtot = 2/6
Rtot = 6/2 = 3 ohm

I = V / Rtotal = 6 volt / 3 ohm
I = 2 Ampere
Jawaban C