hitung lah [7^{0} :(-0,6)^{0} x (\frac{-2}{5})^{-3} ]: (\frac{8}{125})^{-2}
Matematika
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Pertanyaan
hitung lah [7^{0} :(-0,6)^{0} x (\frac{-2}{5})^{-3} ]: (\frac{8}{125})^{-2}
1 Jawaban
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1. Jawaban xkuadratz
[tex]{[7^{0} :(-0,6)^{0} x (\frac{-2}{5})^{-3} ]: (\frac{8}{125})^{-2}} \\ \\ = (1:1x( \frac{5}{-2})^3 ) : ( \frac{125}{8})^2 \\ \\ =( \frac{-8}{125} ):( \frac{125^2}{8^2} ) \\ \\ =( \frac{-8}{125} ).( \frac{8^2}{125^2} ) = \frac{-8^3}{125^3} [/tex]