guys bantu ya ! ( no 4 )

Rumus kalor
Q = m × c × delta t
= 0.25 × 4200 × (100-20)
= 0.25 × 4200× (80)
= 84000 J

Semoga membantu

Q= m×c×(t2-t1)
= 0,25 × 4200 ×(100-20)
=0,25 × 4200 × 80
= 84000 j
Jawabannya B