Jika KbNH4OH =10-5, makatentukan pH100 mL larutan NH4Cl0,01M!

NH4Cl adalah garam asam.

[tex][H^+] = \sqrt { \frac {Kw}{Kb} \times M}[/tex]
[tex][H^+] = \sqrt { \frac {10^{-14}}{10^{-5}} \times 0,1}[/tex]
[tex][H^+] = 10^{-5} M[/tex]
pH = -log[H⁺] = -log(10⁻⁵)
pH = 5