Matematika

Pertanyaan

Nilai x yang memenuhi persamaan 2.³log² x - ³log x³+log 10=10

1 Jawaban

  • 2.³log²x - ³log x³ + 1 = 10
    2.³log²x - 3.³log x + 1 - 10 = 0
    2.³log²x - 3.³log x - 9 = 0
    misal ³log x = p
    2p² - 3p - 9 = 0
    (2p + 3)(p - 6) = 0
    2p + 3 = 0
    p = -3/2
    ³log x = -3/2
    x = 3^(-3/2)
    x = 1 / 3^(3/2)
    x = 1 / (3√3) rasionalkan
    x = (1/9)√3
    atau
    p - 6 = 0
    p = 6
    ³log x = 6
    x = 3^6
    x = 729

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