ada yg bisa nomer 19,20,21? tolong dong hehe
Matematika
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Pertanyaan
ada yg bisa nomer 19,20,21?
tolong dong hehe
tolong dong hehe
1 Jawaban
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1. Jawaban DB45
19. cos C = AC² + BC² - AB² / ( 2)(AC)(BC)
cos C = (4²+4² - (4√2)²) / (2(4)(4) = 0/32
cos C = 0
20.
Tan 60 = AC/AB
AC = AB. tan 60
AC = 4 (√3)
AC = 4√3 cm
21.
a = 4
b = 6
c = 7
S= 1/2 ( a+b+c) =1/2 (4+6+7)
S= 8,5
L = √ [s(s-a)(s-b)(s-c)]
L = √(8,5)(4,5)(2,5)(1)
L = √95,625
L = 9,78