Matematika

Pertanyaan

ada yg bisa nomer 19,20,21?
tolong dong hehe
ada yg bisa nomer 19,20,21? tolong dong hehe

1 Jawaban

  • 19. cos C = AC² + BC² - AB² / ( 2)(AC)(BC)
    cos C = (4²+4² - (4√2)²) / (2(4)(4) = 0/32
    cos C = 0

    20.
    Tan 60 = AC/AB
    AC = AB.  tan 60
    AC = 4 (√3)
    AC  = 4√3 cm

    21.
    a = 4
    b = 6
    c = 7
    S= 1/2 ( a+b+c) =1/2 (4+6+7)
    S= 8,5

    L = √ [s(s-a)(s-b)(s-c)]
    L = √(8,5)(4,5)(2,5)(1)
    L = √95,625
    L = 9,78