mohon dijawab yaa plis fisika

Q Lepas = Q Terima

m1 = 2 kg
m2 = 5 kg
t1 = 100
t2 = 30

2 . 1 . ( 100 - Tc ) = 5 . 1 . ( Tc - 30 )
2( 100 - Tc ) = 5( Tc - 30 )
200 - 2Tc = 5Tc - 150
- 2Tc - 5Tc = - 150 - 200
- 7Tc = - 350
Tc = 50°c

Q1. = Q2
m . c . ( t1 - t ) =m . c . ( t - t2 )
2 . c . (100 - t) = 5 . c . (t - 30)
karena massa jenis air sama..dihilangkan
2.(100-t) = 5.(t-30)
200-2t = 5t-150
200+150 = 5t+2t
350 = 7t
t = 350:7
=50

jadi suhu campurannya adalah 50°c