Besi bermassa 2 kg bersuhu 20° C dicelupkan kedalam air bersuhu 60°C. Suhu campuran menjadi 50°C. Jika kalor yang dilepaskan air sebesar 27.600 Joule, kalor jen

Q lepas = Q terima
m.c.delta t = 27600
2.c. (60-20) =27600
2. c. 40 = 27600
80c = 27600
c = 27600/80 = 345 J/kg derajat C
semoga membantu:)

Dik:
mbesi = 2 kg
T1besi = 20°C
T1air = 60°C
Tc = 50°C
Qlepas air = 27600 J

Dit: cbesi

Jawab:
Qterima = Qlepas
Qbesi = Qair
mbesi . cbesi . DeltaT = 27600 J
2 kg . cbesi . (Tc -T1besi) = 27600 J
2 kg. cbesi .(50-20)°C = 27600 J
2 kg. cbesi . (30)°C = 27600 J
60 kg.°C. cbesi = 27600 J
cbesi = 460 J/kg.°C