Matematika

Pertanyaan

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1 Jawaban

  • 19.
    s.s = 64cm^2
    s^2 = 64cm^2
    s = akar 64 = 8

    EF^2 = AE^2 + AF^2
    EF^2 = 4^2 + 4^2
    EF^2 = 16 + 16
    EF = akar 32 = 4 akar 2 cm

    Ket: AE = AF = 1/2 s

    JK^2 = FJ^2 + FK^2
    JK^2 = (2 akar 2)^2 + (2 akar 2)^2
    JK^2 = 4.2 + 4.2
    JK^2 = 8 + 8 = 16
    JK = Akar 16 = 4 cm

    Ket: FJ = FK = 1/2EF

    L arsir = 2 L trapesium
    L arsir = 2 . 1/2 . (EG+JK) . (1/2.AE)
    L arsir = 2 . 1/2 . (8+4) . (1/2 . 4)
    L arsir = (8+4) . 2
    L arsir = 24
    Jawab: B

    20.
    L arsir = L segitiga
    7 cm^2 = 1/2.AE.BF
    AE.BF = 7 : 1/2 = 7 . 2 = 14

    L Persegi Panjang = 2AE.2BF
    L PP = 4(AE.BF)
    L PP = 4(14)
    L PP = 56 cm^2

    L yg tdk diarsir = L PP - L Arsir
    L yg tdk diarsir = 56 - 7 = 49 cm^2
    Jawab: C

    Sekian. :)
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