hasil dari integral ( x - 1 ) per akar x^2 - 2x dx =

Integral Substitusi

∫ (x-1) / √(x²-2x)  dx = ∫(x-1)(x²-2x)⁻¹/² dx
u  = x² - 2x
du  = (2x - 2) dx --> du = 2(x -1) dx
(x-1) dx  = 1/2 du

∫(x-1)(x²-2x)⁻¹/² dx =  ¹/₂ ∫ u⁻¹/² du
= ¹/₂ (2) u¹/² + c
= u¹/² + c
= √u  +c
= √(x² - 2x)  + c

=