jika ^b log a = -2 dan ^3log b= (³log2) (1+²log4a), maka 4a + b =
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Pertanyaan
jika ^b log a = -2 dan ^3log b= (³log2) (1+²log4a), maka 4a + b =
1 Jawaban
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1. Jawaban whongaliem
^b log a = - 2 ⇒ b^-2 = a
1/b² = a
b² = 1/a
³㏒ b = (³㏒ 2) (1 + ²㏒ 4a)
³㏒ b = ³㏒ 2 + ³㏒ 2 x ²㏒ 4a
³㏒ b = ³㏒ 2 + ³㏒ 4a
³㏒ b = ³㏒ (2 x 4a)
³㏒ b = ³㏒ 8a
b = 8a .... pangkatkan 2
b² = 64 .a²
1/a = 64 .a²
1 = 64 .a³
a³ = 1/64
a = ∛(1/64)
a = 1/4
b² = 1/a
b² = 1 / (1/4)
b² = 4
b = √4
b = 2
4a + b = 4 (1/4) + 2
= 1 + 2
= 3